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NEW QUESTION # 16
Assume you have an automatic module from the module path display-ascii-0.2. jar. Which name is given to the automatic module based on the given JAR file?
- A. Display-ascii
- B. Display-ascii-0
- C. Display.ascii
- D. Display-ascii-0.2
Answer: A
Explanation:
An automatic module name is derived from the name of the JAR file when it does not contain a module-info.class file. If the JAR file has an "Automatic-Module-Name" attribute in its main manifest, then its value is the module name. Otherwise, the module name is derived from the JAR file's name by removing any version numbers and converting it to lower case. Therefore, for a JAR named display-ascii-0.2.jar, the automatic module name would be display-ascii, following these rules.
NEW QUESTION # 17
Given the product class:
And the shop class:
What is the result?
- A. Compilation fails
- B. Cookie 0.0 2.99
- C. An exception is produced at runtime
- D. Cookie 3.99 2.99
- E. Cookie 2.99 2.99
- F. Cookie 0.0 0.0
Answer: A
Explanation:
Explanation
The code fragment will fail to compile because the readObject method in the Product class is missing the
@Override annotation. The readObject method is a special method that is used to customize the deserialization process of an object. It must be declared as private, have no return type, and take a single parameter of type ObjectInputStream. It must also be annotated with @Override to indicate that it overrides the default behavior of the ObjectInputStream class. Without the @Override annotation, the compiler will treat the readObject method as a normal method and not as a deserialization hook. Therefore, the code fragment will produce a compilation error. References: Object Serialization - Oracle, [ObjectInputStream (Java SE 17 & JDK 17) - Oracle]
NEW QUESTION # 18
Given:
Which action enables the code to compile?
- A. Replace 15 with item.display (''Flower'');
- B. Replace 2 with static string name;
- C. Replace 7 with public void display (string design) {
- D. Replace 3 with private static void display () {
Answer: C
Explanation:
Explanation
The answer is C because the code fragment contains a syntax error in line 7, where the method display is declared without any parameter type. This causes a compilation error, as Java requires the parameter type to be specified for each method parameter. To fix this error, the parameter type should be added before the parameter name, such as string design. This will enable the code to compile and run without any errors.
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Java Methods
NEW QUESTION # 19
Given the code fragment:
What is the result?
- A. false 1
ture 2 - B. false 1
false 2 - C. falase 0
true 1 - D. true 1
false 2
Answer: C
Explanation:
The code fragment is comparing the values of a, b, and c using the < and > operators. The first comparison, d, is checking if a is less than b and greater than c. Since a is equal to 2, b is equal to -2, and c is equal to -4, this comparison will evaluate to true. The second comparison, e, is checking if a is greater than b and a is greater than c. Since a is equal to 2, b is equal to -2, and c is equal to -4, this comparison will evaluate to false. Therefore, the result will be true 1 false 2. Reference: Operators (The Java™ Tutorials > Learning the Java Language - Oracle
NEW QUESTION # 20
Given:
and the code fragment:
- A. 100.00 CellPhone,ToyCar
- B. 100.00
CellPhone,ToyCar,Motor,Fan - C. 300.00
CellPhone.ToyCar - D. 300.00
CellPhone,ToyCar,Motor,Fan
Answer: D
Explanation:
The code fragment is using the Stream API to perform a reduction operation on a list of ElectricProduct objects. The reduction operation consists of three parts: an identity value, an accumulator function, and a combiner function. The identity value is the initial value of the result, which is 0.0 in this case. The accumulator function is a BiFunction that takes two arguments: the current result and the current element of the stream, and returns a new result. In this case, the accumulator function is (a,b) -> a + b.getPrice (), which means that it adds the price of each element to the current result. The combiner function is a BinaryOperator that takes two partial results and combines them into one. In this case, the combiner function is (a,b) -> a + b, which means that it adds the two partial results together.
The code fragment then applies a filter operation on the stream, which returns a new stream that contains only the elements that match the given predicate. The predicate is p -> p.getPrice () > 10, which means that it selects only the elements that have a price greater than 10. The code fragment then applies a map operation on the filtered stream, which returns a new stream that contains the results of applying the given function to each element. The function is p -> p.getName (), which means that it returns the name of each element.
The code fragment then calls the collect method on the mapped stream, which performs a mutable reduction operation on the elements of the stream using a Collector. The Collector is Collectors.joining (","), which means that it concatenates the elements of the stream into a single String, separated by commas.
The code fragment then prints out the result of the reduction operation and the result of the collect operation, separated by a new line. The result of the reduction operation is 300.00, which is the sum of the prices of all ElectricProduct objects that have a price greater than 10. The result of the collect operation is CellPhone,ToyCar,Motor,Fan, which is the concatenation of the names of all ElectricProduct objects that have a price greater than 10.
Therefore, the output of the code fragment is:
300.00 CellPhone,ToyCar,Motor,Fan
NEW QUESTION # 21
Given:
Which action enables the code to compile?
- A. Replace 15 with item.display (''Flower'');
- B. Replace 2 with static string name;
- C. Replace 7 with public void display (string design) {
- D. Replace 3 with private static void display () {
Answer: C
Explanation:
The answer is C because the code fragment contains a syntax error in line 7, where the method display is declared without any parameter type. This causes a compilation error, as Java requires the parameter type to be specified for each method parameter. To fix this error, the parameter type should be added before the parameter name, such as string design. This will enable the code to compile and run without any errors. Reference:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Java Methods
NEW QUESTION # 22
Given:
What is the result?
- A. D D D
- B. B A D
- C. D A D
- D. B A C
Answer: B
Explanation:
The answer is C because the code demonstrates the concept of method overloading and type conversion in Java. Method overloading allows different methods to have the same name but different parameters. Type conversion allows values of one data type to be assigned to another data type, either automatically or explicitly. In the code, the class Test has four methods named sum, each with different parameter types: int, float, and double. The main method creates an instance of Test and calls the sum method with different arguments. The compiler will choose the most specific method that matches the arguments, based on the following rules:
If there is an exact match between the argument types and the parameter types, that method is chosen.
If there is no exact match, but there is a method with compatible parameter types, that method is chosen. Compatible types are those that can be converted from one to another automatically, such as int to long or float to double.
If there is more than one method with compatible parameter types, the most specific method is chosen. The most specific method is the one whose parameter types are closest to the argument types in terms of size or precision.
In the code, the following method calls are made:
test.sum(10, 10.5) -> This matches the sum(int a, float b) method exactly, so it is chosen. The result is 20.5, which is converted to int and printed as 20 (B).
test.sum(10) -> This does not match any method exactly, but it matches the sum(double a) method with compatible types, as int can be converted to double automatically. The result is 10.0, which is printed as 10 (A).
test.sum(10.5, 10) -> This does not match any method exactly, but it matches two methods with compatible types: sum(float a, float b) and sum(double a, double b). The latter is more specific, as double is closer to the argument types than float. The result is 20.5, which is printed as 20 (D).
Therefore, the output is B A D. Reference:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Method Overloading in Java
Type conversion in Java with Examples
Java Method Overloading with automatic type conversions
NEW QUESTION # 23
Given the code fragment:
What is the result?
- A. PT5000PT60MP6D
- B. 5000$60M6D
- C. $SIM6D
- D. PT5SPTIMP6D
Answer: A
Explanation:
The code fragment is creating a Duration object with a value of 5000 milliseconds, then printing it. Then, it is creating another Duration object with a value of 60 seconds, then printing it. Finally, it is creating a Period object with a value of 6 days, then printing it. The output will be "PT5000PT60MP6D". Reference: https://docs.oracle.com/javase/8/docs/api/java/time/Duration.html, https://docs.oracle.com/javase/8/docs/api/java/time/Period.html
NEW QUESTION # 24
Given the code fragment:
What is the result?
- A. 010 optional (Newyear)
- B. True true false NewYear
- C. False true true optional (Newyear)
- D. 0110
Answer: C
Explanation:
The code fragment is using the stream methods allMatch, anyMatch, noneMatch, and findFirst on a list of strings called specialDays. These methods are used to perform matching operations on the elements of a stream, such as checking if all, any, or none of the elements satisfy a given predicate, or finding the first element that matches a predicate1. The predicate in this case is that the string equals "Labour" or "Halloween". The output will be:
False: because not all of the elements in specialDays are equal to "Labour" or "Halloween".
true: because at least one of the elements in specialDays is equal to "Labour" or "Halloween".
true: because none of the elements in specialDays are equal to both "Labour" and "Halloween".
Optional[NewYear]: because the first element in specialDays that matches the predicate is "NewYear", and the findFirst method returns an Optional object that may or may not contain a non-null value2.
NEW QUESTION # 25
Given:
What is the result
- A. UnDefined
- B. Marketing
Finance
Technical - C. Marketing
- D. Marketing
Undefined
Answer: A
Explanation:
Explanation
The code fragment is using the switch statement with the new Java 17 syntax. The switch statement checks the value of the variable desig and executes the corresponding case statement. In this case, the value of desig is
"CTO", which does not match any of the case labels. Therefore, the default case statement is executed, which prints "Undefined". The other case statements are not executed, because there is no fall through in the new syntax. Therefore, the output of the code fragment is:
Undefined
NEW QUESTION # 26
Given the directory structure:
Given the definition of the Doc class:
Which two are valid definition of the wordDoc class?
- A. Package p1, p2;
Public sealed class WordDoc extends Doc () - B. Package p1,
non-sealed abstract class WordDoc extends Doc () - C. Package p1;
Public non-sealed class wordDoc extends Doc () - D. Package p1;
Public class wordDoc extends Doc () - E. Package p1;
Public final class WordDoc extends Doc () - F. Package p1, p2;
Public non-sealed class WordDoc extends Doc ()
Answer: C,E
Explanation:
The correct answer is A and F because the wordDoc class must be a non-sealed class or a final class to extend the sealed Doc class. Option B is incorrect because the wordDoc class must be non-sealed or final. Option C is incorrect because the wordDoc class cannot be in a different package than the Doc class. Option D is incorrect because the wordDoc class cannot be a sealed class. Option E is incorrect because the wordDoc class cannot be an abstract class. Reference: Oracle Certified Professional: Java SE 17 Developer, 3 Sealed Classes - Oracle Help Center
NEW QUESTION # 27
Given:
Which statement is true while the program prints GC?
- A. Only the object referenced by t2 is eligible for garbage collection.
- B. None of the objects are eligible for garbage collection.
- C. Both the objects previously referenced by t1 are eligible for garbage collection.
- D. Only one of the objects previously referenced by t1 is eligible for garbage collection.
Answer: C
NEW QUESTION # 28
Given the code fragment:
Which code fragment invokes all callable objects in the workers set?
- A.
- B.
- C.
- D.
Answer: D
Explanation:
Explanation
The code fragment in Option C invokes all callable objects in the workers set by using the ExecutorService's invokeAll() method. This method takes a collection of Callable objects and returns a list of Future objects representing the results of the tasks. The other options are incorrect because they either use the wrong method (invokeAny() or submit()) or have syntax errors (missing parentheses or semicolons). References: AbstractExecutorService (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 29
Given:
What is the result?
- A. 100
100
1000 - B. 1001
100
1000 - C. 101
101
1000 - D. 1001
1001
1000
Answer: B
Explanation:
Explanation
The code fragment is using the bitwise operators & (AND), | (OR), and ^ (XOR) to perform operations on the binary representations of the integer values. The & operator returns a 1 in each bit position where both operands have a 1, the | operator returns a 1 in each bit position where either operand has a 1, and the ^ operator returns a 1 in each bit position where only one operand has a 1. The binary representations of the integer values are as follows:
1000 = 1111101000
100 = 1100100
101 = 1100101
The code fragment performs the following operations:
x = x ^ y; // x becomes 1111010101, which is 1001 in decimal
y = x ^ y; // y becomes 1100100, which is 100 in decimal
x = x ^ y; // x becomes 1100101, which is 101 in decimal
The code fragment then prints out the values of x, y, and z, which are 1001, 100, and 1000 respectively.
Therefore, option D is correct.
NEW QUESTION # 30
Given the content of the in. tart file:
23456789
and the code fragment:
What is the content of the out .txt file?
- A. 01234567801234
- B. 012345678901234
- C. 0123456789
- D. 012345678
- E. 0123456789234567
- F. 01234567
Answer: C
Explanation:
The answer is D because the code fragment reads the content of the in.txt file and writes it to the out.txt file. The content of the in.txt file is "23456789". The code fragment uses a char array buffer of size 8 to read the content of the in.txt file. The while loop reads the content of the in.txt file and writes it to the out.txt file until the end of the file is reached. Therefore, the content of the out.txt file will be "0123456789".
NEW QUESTION # 31
Given the code fragment:
Which action sorts the book list?
- A. At Line n2, replace compareTo () with compare ().
- B. At Line n2, replace books,sort() with books.stream().sort(0.
- C. At Line n1, convert type to mutable array type.
- D. At line n1, convert books type to mutable ArrayList type.
Answer: A
Explanation:
Explanation
The code fragment is trying to sort a list of books using the Collections.sort() method. The correct answer is D, because the compareTo() method is not the correct way to compare two objects in a Comparator. The compare() method is the correct way to compare two objects in a Comparator and return an int value that indicates their order1. The compareTo() method is used to implement the Comparable interface, which defines the natural order of objects of a class2. The other options are incorrect because they either do not change the type of the list, which is already mutable, or they do not use the correct syntax for sorting a stream, which requires a terminal operation such as collect()3. References: Comparator (Java SE 17 & JDK 17), Comparable (Java SE 17 & JDK 17), Stream (Java SE 17 & JDK 17)
NEW QUESTION # 32
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The 1Z0-829 exam is a two-hour exam that consists of 80 multiple-choice questions. 1z1-829 exam is designed to test your knowledge and skills in developing applications using Java SE 17. 1z1-829 exam is available in English and Japanese, and it can be taken at any Pearson VUE testing center. 1z1-829 exam fee is $245, and you will receive your results immediately after completing the exam.
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