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SAP Certified Application Associate - Crystal Reports 2008 Sample Questions:

1. In a new Crystal report you must create a formula to split the string "Up Down Sideways" into an array with three elements then display the third element of the array. Which formula meets the requirement?

A) Split("Up Down Sideways", ", ")(3)
B) Split("Up Down Sideways", ", ")[3]
C) Split("Up Down Sideways", " ")[3]
D) Split("Up Down Sideways", " ")(3)

2. How do you add fields to an existing report?

A) Right-click the report section and select the Add Field option.
B) Right-click the report section and select the Insert Field option.
C) Add report fields using the Field Explorer.
D) Add report fields using the Report Explorer.

3. You are designing a Crystal report that summarizes customer orders by country, then by state, then by city and by customer ID. You want the report to print each country on a new page. The first page should display a bar chart showing Total Sales by Country group in the Report Header and as much of the first country as can be displayed. The last page should show the summary for the last country and the grand total for the entire report. Which step can you perform in the Section Expert to achieve the design goal?

A) Format the New Page After property for Group Header #1 using the formula "not onlastrecord"
B) Conditionally format the New Page After property for Group Footer #1 using the formula "not onlastrecord"
C) Set New Page After on for the Report Header section
D) Set New Page After on for Group Footer #1

4. You need to modify an existing calculated member in a Cross-Tab. Which three formulas can you edit? (Choose three.)

A) Header formula
B) Row value formula
C) Column value formula
D) Insertion formula

5. Which two statements are true limitations of the Crystal formula anguage? (Choose two.)

A) The maximum size of an array is 1,000 elements.
B) The minimum size of an array is zero.
C) The maximum number of loop condition evaluations per evaluation of a formula is 100,000.
D) The maximum length of a string constant is 12,256 characters.

Solutions: